Created attachment 43023 [details]
example code, visualizing the behavior from above

Assume `d` as a normal double variable.
Executing
`sscanf ( "0x", "%lf", &d )`
returns `0` and `d` isn't modified, 'cause the string can't be parsed.
I think that 0x indicates in correspondence with `%lf`, that there seem to be a maybe slightly incomplete hex-float.

But wouldn't it be a better behavior if this statement is correctly parsed into the double `d` with the value `0`, 'cause ignoring the `x` and correctly parsing `0` as well as assuming that `0x` originally means `0x0` is a much more thought-out behavior than just saying "sry, but this can't be parsed, so it's better doing nothing"?
Even though `sscanf ( "0x", "%i", &i )` returns successfully `1` and the integer value `i` is going to have the value `0`. Furthermore e.g. BSD' versions of GCC correctly parses the 0x-lf case...

I'm using a x86_64-pc-linux-gnu 4.14.9-Linux to compile the code without any significant options (no compiler warnings present).
Thanks!