Sorry to mention aliasing again, but is the standard IN6_ARE_ADDR_EQUAL really wrong?

[Andreas Schwab]

Andrew Haley <aph@redhat.com> writes:

> On 01/10/2010 12:39 PM, Andreas Schwab wrote:
>> Andrew Haley <aph@redhat.com> writes:
>> 
>>> Why do you say the effective type is different?
>> 
>> The object type is uint8_t, but accessed as uint32_t.  That is
>> undefined.
>
> Unless uint8_t is a character type, as I understand it.

In which way does it make a difference?  For aliasing consideration,
only the type of access matters.

Andreas.

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Andreas Schwab, schwab@linux-m68k.org
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