Overload resolution compilation error

Ling-hua Tseng uranus@it.muds.net
Fri Jul 20 00:55:00 GMT 2007

On Thu, 19 Jul 2007 21:19:09 -0300, Rodolfo Lima wrote
> In my first example, the target type is the type of the address 
> expression, 
It cannot be treated as the target in paragraph 1 of section 13.4 (ISO/IEC 
Again, here is the list of possible targets:
1. an object or reference being initialized (8.5, 8.5.3),
2. the left side of an assignment (5.17),
3. a parameter of a function (5.2.2),
4. a parameter of a user-defined operator (13.5),
5. the return value of a function, operator function, or conversion (6.6.3),
6. an explicit type conversion (5.2.3, 5.2.9, 5.4), or
7. a non-type template-parameter (14.3.2).

Obviously, {1, 2, 4, 5, 6, 7} are not matched.
Maybe you think that the item 3 is matched.
Unfortunately, it stands for the non-template functions.

BTW, here are two important sentences after the 7 items:
"The overloaded function name can be preceded by the & operator.
An overloaded function name shall not be used without arguments in contexts 
other than those listed."

Here is you original example code:
#include <iostream>

using namespace std;

void print() { cout << "null" << endl; }
template<int i> void print() { cout << i << endl; }
template<int i, int j> void print() { cout << i << ' ' << j << endl; }

template <class F> void call(F f)

int main()
//  proper way (according to g++) to call non-templated print
//  call(static_cast<void(*)()>(&print));

    return 0;

If you want to match the item 3, you have to replace the definition of call<>
() to a non-template function:
void call(void (*f)())
And then it can be passed by g++.

The 2nd line of main() which you marked is matched by item 6.
Hence it can also compiled by g++.

Again, the set of overloaded function has never contain anything in your 
original example.
It's because you don't have any targets which are matched to any items of 
list in paragraph 1 of section 13.4.
Maybe you think that it contained the non-template one at begining.
No, it's also not in the set.

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