Bug in std::floor?
Jonathan Wakely
jwakely@redhat.com
Wed Nov 8 22:25:00 GMT 2017
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On 08/11/17 23:13 +0200, Nil Geisweiller wrote:
>Hi,
>
>The following
>
>---------------------------------------------------------------------
>#include <iostream>
>#include <cmath>
>
>int main()
>{
> double v = 4.6;
> std::cout << "v = " << v << std::endl;
> std::cout << "v*100 = " << v*100 << std::endl;
> std::cout << "floor(v*100) = " << std::floor(v*100) << std::endl;
>}
>---------------------------------------------------------------------
>
>outputs
>
>------------------
>v = 4.6
>v*100 = 460
>floor(v*100) = 459
>------------------
>
>It that a bug?
No.
Try:
#include <iostream>
#include <iomanip>
#include <cmath>
int main()
{
double v = 4.6;
std::cout << "v = " << std::setprecision(17) << v << std::endl;
std::cout << "v*100 = " << std::setprecision(16) << v*100 << std::endl;
std::cout << "floor(v*100) = " << std::floor(v*100) << std::endl;
}
>If so where is the implementation of floor (so I can study and fix)? I
>know it is supposed to be in gcc/builtins.c but I don't understand
>where.
It doesn't necessarily use __builtin_floor anyway (without optimzation
it just calls the C library's floor(double) function).
>You may run the program above from http://tpcg.io/QNfhYr
>
>Thanks,
>
>Nil
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