Re: error: unable to find numeric literal operator ‘operator"" f’

[Florian Weimer]

On 02/13/2014 06:22 PM, Jonathan Wakely wrote:
> On 13 February 2014 03:23, Florian Weimer wrote:
>>
>> I think the ""f operator has not been implemented in C++1y mode, either
>> because it's not actually part of the standard or no one has found the time
>> to implement it yet.
>
> f is not a user-defined literal operator, it's a core language feature
> present in C and C++, but not valid on integer-literals such as 42.

I think the expectation here is that C++14 will provide a 
language-defined literal operator that will make this legal.  I don't if 
this expectation is warranted, not having consulted the standard.

-- 
Florian Weimer / Red Hat Product Security Team