What's the difference between (*(x)).a and (x)->a

holderlin holderlinzhang@gmail.com
Wed Jan 21 03:07:00 GMT 2009

I see. Thanks, guys.

On Wed, Jan 21, 2009 at 8:03 AM, Lawrence Crowl <crowl@google.com> wrote:
> On 1/20/09, Andrew Haley <aph@redhat.com> wrote:
>> This shouldn't have been posted to gcc@gcc.gnu.org, which is for gcc
>> development only.  Redirecting.
>> holderlin wrote:
>> > Is there any difference between (*(x)).a and (x)->a, if x is an
>> > expression which generates a struct pointer.
>> No.  The standard says that in all cases they are the same.
> Just to be sure that there is no miscommunication, Andrew is assuming
> that by gcc you mean gcc when compiling C.
> They are the same for the C language, but may be different in C++
> if the struct has overloaded the * or -> operators.
> --
> Lawrence Crowl

Holderlin Zhang
Department of Applied Math., Nankai University

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