What's the difference between (*(x)).a and (x)->a

[John Fine]

Lawrence Crowl wrote:
>> holderlin wrote:
>>     
>>> Is there any difference between (*(x)).a and (x)->a, if x is an
>>> expression which generates a struct pointer.
>>>       
> They are the same for the C language, but may be different in C++
> if the struct has overloaded the * or -> operators.
>   
Can they be different in C++ ?

A key phrase in the question is "x is an expression which generates a 
struct pointer."

You can overload the meaning of * or -> if x is a struct.  I thought you 
couldn't overload them if x is a pointer.