[Bug c++/15359] errors specializing a template class of a template class

[igodard at pacbell dot net]

------- Additional Comments From igodard at pacbell dot net  2004-05-10 19:37 -------
But that doesn't work either (or rather it does, but it's not my case). My case is (using your suggested code):

template<typename E>
struct  F {
    template<typename G>
    struct H {
        };
    H<E>    h;
    };

template<>
template<typename E>
struct F<E>::H<int> {
public:
    int i;
    };

int main() {
    return 0;
    }


That is, no matter what the template argument E to the outer template H is, I want the inner template H to specialize as specified when invoked with argument G as int. Note that the inner template does not depend in any way on either the outer template or its argiment. My reading of the standard says that this is legal (though I admit it is impossible to tell for the merely mortal), and gcc is not accepting it - nor any of the other constructions I've tried.

Is the above code actually legal? If not, is there a way to get the semantics I'm looking for? The obvious approach of simply making the specialization of H local to G (and so using whatever E is present) seems to be rejected, although for the life of me I can't guess why that would be so.

Ivan

-- 
           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|RESOLVED                    |UNCONFIRMED
         Resolution|INVALID                     |


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=15359