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Re: demengler in libstdc++ is changed


On Fri, 14 Nov 2003, Matt Austern wrote:

> Example: _Z3fooPKi could reasonably be demangled as foo(const int*),
> or foo(int const*), or foo(int const *), or a number of other
> choices.  All are correct; as far as the compiler is concerned, there
> is no difference between them.  Programmers use those forms
> interchangeably, or choose between them on stylistic grounds.  In
> my opinion a demangler that chose any of those forms is correct.
> 
> 			--Matt

I'm confused. To me, these are not the same.

foo(const int *) is a function which takes "pointer to a const int".

foo (int const *) is a function which takes "const pointer to an int".

What am I missing?

Toshi



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