[Bug c/47143] warning about const multidimensional array as function parameter

["rogi at linuxmail dot org" <gcc-bugzilla at gcc dot gnu dot org>]

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=47143

Igor <rogi at linuxmail dot org> changed:

           What    |Removed                     |Added
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             Status|RESOLVED                    |UNCONFIRMED
         Resolution|INVALID                     |

--- Comment #5 from Igor <rogi at linuxmail dot org> 2011-01-01 15:42:34 UTC ---
(In reply to comment #4)
> If you want to use const here only on the callee side then you will need to use
> casts.  I meant what I said: you are passing "pointer to array[4] of double",
> with no const in there, to a function expecting "pointer to array[4] of const
> double", and this is not a case permitted by C99 6.5.16.1#1.  C does not have a
> type "pointer to const array[4] of double".

Let me see if I understood.

const double a[4][4]

will become a "pointer to array of consts". So when i call my function passing
a "pointer to array", teh conversion fails since it's only allowed to apply teh
qualifier (const) to teh _pointer type_, which is an array, and not to it's
elements as teh function was expecting.

Correct me if I'm wrong again please and thanks for your patience.