[Bug c++/11648] New: G++ parse error for simple template code

["wwieser at gmx dot de" <gcc-bugzilla at gcc dot gnu dot org>]

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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=11648

           Summary: G++ parse error for simple template code
           Product: gcc
           Version: 3.3.1
            Status: UNCONFIRMED
          Severity: normal
          Priority: P2
         Component: c++
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: wwieser at gmx dot de
                CC: gcc-bugs at gcc dot gnu dot org
 GCC build triplet: i686-linux-gnu
  GCC host triplet: i686-linux-gnu
GCC target triplet: i686-linux-gnu

Trying to compile following code... 
 
-----------------<test.cc>--------------------- 
struct A 
{ 
	template<class T>T *foo(); 
}; 
 
template<class T>void bar(A *a) 
{ 
	a->foo<T>(); 
} 
---------------------------------------------- 
 
...I get the following parse error:  
test.cc: In function `void bar(A*)': 
test.cc:8: error: parse error before `>' token 
 
I am the opinion that the code above is legal C++.  
 
If I replace the T by a #define, things work well:  
 
--------------<good.cc>------------------ 
struct A 
{ 
	template<class T>T *foo(); 
}; 
 
#define T int 
void bar(A *a) 
{ 
	a->foo<T>(); 
} 
----------------------------------------- 
 
Maybe there is a way how one could use brackets to  
make the parser happy, but I was not able to find such  
a construct.