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Re: c++/8772: Segmentation fault on 3 lines of template code
- From: Gabriel Dos Reis <gdr at integrable-solutions dot net>
- To: bangerth at dealii dot org
- Cc: gcc-bugs at gcc dot gnu dot org, zack at codesourcery dot com, pcarlini at unitus dot it, sneechy at hotmail dot com, gcc-gnats at gcc dot gnu dot org
- Date: 02 Dec 2002 23:49:28 +0100
- Subject: Re: c++/8772: Segmentation fault on 3 lines of template code
- Organization: Integrable Solutions
- References: <20021202204531.25509.qmail@sources.redhat.com>
bangerth@dealii.org writes:
| Synopsis: Segmentation fault on 3 lines of template code
|
| State-Changed-From-To: open->analyzed
| State-Changed-By: bangerth
| State-Changed-When: Mon Dec 2 12:45:29 2002
| State-Changed-Why:
| Others have confirmed this already.
|
| However, just for the record: I fail to see how this can be
| made legal: when you write A<n>::B to denote the template
| type, B is a template dependent type, and one would think
| one has to write a "typename" somewhere. But then we have
| typename A<n>::B
| which is not the name of a type, but of a template. I don't
| know what the standard says here, but I don't see a way to
| make it legal in any case.
This case seems to be forgotten by the standard. I think the
following should make GCC happy.
template<int n>
struct D {
enum {
v = C<A<n>::template B>::v
};
};
Note the "template" keyword in front of B.
The closest you can find in the standard is 14.2/
4
When the name of a member template specialization appears after . or
-> in a postfix-expression, or after nested-name-specifier in a
qualified-id, and the postfix-expression or qualified-id explicitly
depends on a template-parameter (14.6.2), the member template name
must be prefixed by the keyword template. Otherwise the name is
assumed to name a non-template. [ example not reproduced ]
5
If a name prefixed by the keyword template is not the name of a
member template, the program is ill-formed.
-- Gaby