When in an std::unexpected_handler, backtrace_symbols returns a trace with functions not even called at all.  

I noticed strange functions to appear on the trace, and missed functions that should be there.

I reproduced it with the following minimal code:

#include <exception>
#include <execinfo.h>

extern "C" void my_unexpected_handler() {
        void* trace[100];
        int size = backtrace(trace, 100);
        backtrace_symbols_fd(trace, size, 2);
}

void throw_0() throw() {
        throw 0;
}

extern "C" void not_called_at_all_but_appearing_on_the_backtrace() { }

extern "C" int main(int, char*[]) {
        std::set_unexpected(my_unexpected_handler);
        throw_0();
        return 0;
}

I compile this with: g++ -g -rdynamic <filename>
It then produces:

./a.out(my_unexpected_handler+0x1f)[0x8048973]
/usr/lib/libstdc++.so.6(+0xbd465)[0xb7853465]
/usr/lib/libstdc++.so.6(__cxa_call_unexpected+0x45)[0xb78528b5]
./a.out(not_called_at_all_but_appearing_on_the_backtrace+0x0)[0x80489dc]
./a.out(main+0x1a)[0x80489fb]
/lib/i686/cmov/libc.so.6(__libc_start_main+0xe6)[0xb7621c76]
./a.out[0x80488c1]
terminate called after throwing an instance of 'int'
Aborted

As you can see, "not_called_at_all_but_appearing_on_the_backtrace" is not called anywhere, but yet it is on the stack trace.

The function throw_0 however is missing.

I believe this is a bug.  If not, what is going on here?

Best regards
Erik Groeneveld