std::allocator should use sized delete

[Victor via libstdc++]

Hi!

C++14 introduced function ::operator delete(void * , 
size_t ) but libstdc++ std::allocator::deallocate() still 
uses the unsized version. Shouldn't it look like

void deallocate(pointer __p, size_type __n)
{
     ::operator delete(__p
#if __cpp_sized_deallocation
         , __n * sizeof(_Tp)
#endif
     );
}

?