parallel equal not parallel
Johannes Singler
singler@kit.edu
Fri Nov 5 17:13:00 GMT 2010
On 11/04/2010 10:53 PM, Paolo Carlini wrote:
> On 11/04/2010 09:48 PM, François Dumont wrote:
>> So it uses the normal mismatch algo, IMO it should be:
>>
>> template<typename _IIter1, typename _IIter2>
>> inline bool
>> equal(_IIter1 __begin1, _IIter1 __end1, _IIter2 __begin2)
>> {
>> return mismatch(__begin1, __end1, __begin2).first == __end1;
>> }
>>
>> template<typename _IIter1, typename _IIter2, typename _Predicate>
>> inline bool
>> equal(_IIter1 __begin1, _IIter1 __end1, _IIter2 __begin2,
>> _Predicate __pred)
>> {
>> return mismatch(__begin1, __end1, __begin2, __pred).first ==
>> __end1;
>> }
>>
>> Agree ?
> Johannes?
Looks reasonable. I'm going to regression test this patch.
Johannes
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