std::function with std::unique_ptr argument

Rodolfo Lima rodolfo@rodsoft.org
Fri Jun 5 11:45:00 GMT 2009


Hi, I'm trying to use a std::function with std::unique_ptr arguments but
the std::function invocation ends up using std::unique_ptr copy ctor,
which is private/deleted.

Since std::function is a forward call wrapper, its operator() should
have forwarded properly its arguments to the wrapped function, but

M_invoker(_M_functor, __args...);

and

(*_Base::_M_get_pointer(__functor))(__args...);


doesn't seem to do that. IMHO it should be

_M_invoker(_M_functor, std::forward<_ArgTypes>(__args)...);

(*_Base::_M_get_pointer(__functor))(std::forward<_ArgTypes>(__args)...);


Any objections?

Regards,
Rodolfo Lima



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