About std::vector::resize().

[Martin Sebor]

Carlo Wood wrote:

> On Tue, May 25, 2004 at 01:05:04PM -0600, Martin Sebor wrote:
> 
>>Theodore Papadopoulo wrote:
>>The code below must not abort for any (n > 0) but if resize()
>>constructed a new vector and swapped *this for it, it would.
>>
>>    std::vector<T> v;
>>    v.resize (1);
>>    v.reserve (n);
>>    T *p = &v [0];
>>    v.resize (n);   // must not reallocate
> 
> 
> Because the (reserved) "size" is already n there is no need
> for reallocation - so the mentioned algorithm will not
> be used.

Ah. Sorry for the misunderstanding.

FYI, the "reserved size" of a vector is known as its capacity :)

Martin