SEGV fault when using wchar_t streams

[Rob Lugt]

Did anybody else try this out?  Is 
this the correct group to post bugs to?
 
I now have a temporary fix for this.  
If I add a line before (5):     
5      std::wcout.width(1);
 
setting the width to 1 prior to outputing 
the wchar_t fixes the problem.
 
I stumbled on the width fix by stepping 
through the code with gdb.  I was surprised to see that a line in 
bits/ostream.tcc initialising __w was not executed (the debugger jumped over 
it).  Why would this be?
 
 template<typename _CharT, typename 
_Traits>     basic_ostream<_CharT, 
_Traits>&     operator<<(basic_ostream<_CharT, 
_Traits>& __out, _CharT __c)     
{       typedef basic_ostream<_CharT, _Traits> 
__ostream_type;       __ostream_type::sentry 
__cerb(__out);       if 
(__cerb)      {        
try {          streamsize __w = 
__out.width();              
<<<<--- debugger jumps over this 
line          _CharT 
__pads[__w];          __pads[0] = 
__c;          streamsize __len = 
1;          if (__w > 
__len)            
{       _S_pad_char(__out, __pads, &__c, __w, 
__len);       __len = 
__w;            
}          __out.write(__pads, 
__len);          
__out.width(0);        
}        catch(exception& 
__fail){          // 27.6.1.2.1 
Common requirements.          // Turn 
this on without causing an ios::failure to be 
thrown.          
__out.setstate(ios_base::badbit);          
if ((__out.exceptions() & ios_base::badbit) != 
0)            
throw;        }      
}       return __out;     
}
 
 
 
>I compile the following program with 
./g++ -fhonor-std 
>
>      1 
#include <iostream> >      2 int main(int 
argc, char* argv[]) >      3 
{ >      4     std::wcout 
<< L"H"; >      5     
std::wcout << L'i' << std::ends << 
std::endl;    // This appears to be the problem 
line >      6     std::wcout 
<< L"This is going to die - bye" << 
std::endl; >      7 } ÂÂ