Controlling the garbage collector (GC) at RT?
Martin Egholm Nielsen
martin@egholm-nielsen.dk
Sat Feb 26 20:09:00 GMT 2005
>> You also need to touch the resulting memory. Try something like
>> char *v = sbrk( 1000000 );
>> for (char *p = v; p < p + 1000000; ++p) *p = 42;
>> in the loop.
> I'll try something similar tomorrow, thanks alot - although I will need
> modify the ever true statement "p < p + 1M" to "p < v + 1M"...
So, now I tried this:
#include <unistd.h>
int main( int i )
{
while ( 1 ) {
char *v = sbrk( 1000000 );
char *p;
for (*p = v; p < v + 1000000; ++p) {
*p = 42;
} // for
printf( "%x\n\n", v );
} // while
} // main
And still nothing happens with the memory consumption, although the
pointer ends up at 0xffffffff...
Weird?!
// Martin
>
> I'll return in the morrow...
>
> // Martin
>
>>> -----Original Message-----
>>> From: java-owner@gcc.gnu.org [mailto:java-owner@gcc.gnu.org] On
>>> Behalf Of Martin Egholm Nielsen
>>> Sent: Wednesday, February 23, 2005 12:04 AM
>>> To: java@gcc.gnu.org
>>> Subject: Re: Controlling the garbage collector (GC) at RT?
>>>
>>>
>>>
>>>> It seems to me that the only problem here is that this
>>>
>>>
>>> still seems to
>>>
>>>> happen with overcommit-accounting set to 2.
>>>
>>>
>>>> I would expect that you can reproduce this problem with a
>>>
>>>
>>> program that
>>>
>>>> alternately allocates a few MB with sbrk, and then touches the
>>>> allocated memory. If you can't, there's something really
>>>
>>>
>>> weird going
>>>
>>>> on here. If you can, it'll give you a test case for the kernel people.
>>>
>>>
>>> I tried the following:
>>>
>>> #include <unistd.h>
>>>
>>> int main( int i )
>>> {
>>> while ( 1 ) {
>>> void *v = sbrk( 100000 );
>>> // sleep( 1 );
>>> } // while
>>> } // main
>>>
>>> But that doesn't result in anything - the memory usage for the
>>> application does not grow...
>>> Are there anything else I should do to allocate the memory?
>>>
>>> BR,
>>> Martin
>>>
>>>
>>>> Hans
>>>>
>>>> On Wed, 16 Feb 2005, Martin Egholm Nielsen wrote:
>>>>
>>>>
>>>>
>>>>> Hi Hans,
>>>>>
>>>>>
>>>>>
>>>>>>>> It would indeed be interesting to know why the Linux kernel
>>>>>
>>>>>
>>>>>>>> kills the application rather than returning failure.
>>>>>
>>>>>
>>>>>>> Sure, but how to do that? Any guidelines?
>>>>>>
>>>>>>
>>>>>> What do you see on the console? Anything in the system log? Does
>>>>>> strace tell you anything?
>>>>>
>>>>>
>>>>> Below is the last part of "strace -f -F -i -v". It doesn't
>>>
>>>
>>> really look
>>>
>>>>> like there's anything of value?
>>>>>
>>>>> // Martin
>>>>>
>>>>> [pid 75] [0f833558] write(1, "*** MEM CHUNK TAKEN:
>>>
>>>
>>> 8388608\n", 29***
>>>
>>>>> MEM CHUNK TAKEN: 8388608
>>>>> ) = 29
>>>>> [pid 75] [0f839834] brk(0x12d15000) = 0x12d15000
>>>>> [pid 75] [0f839834] brk(0x12d25000) = 0x12d25000
>>>>> [pid 75] [0f81126c] getpid() = 75
>>>>> [pid 75] [0f799444] kill(77, SIGPWR <unfinished ...>
>>>>> [pid 76] [0f840e2c] <... poll resumed> [{fd=3, events=POLLIN,
>>>>> revents=POLLIN}
>>>>> ], 1, 2000) = 1
>>>>> [pid 75] [0f799444] <... kill resumed> ) = 0
>>>>> [pid 76] [0f81127c] getppid() = 75
>>>>> [pid 76] [0f833548] read(3,
>>>>> "\20\7/\234\0\0\0\4\17\374$0\20\7/\240$\0\0B\17\3
>>>>> 72j(\177"..., 148) = 148
>>>>> [pid 76] [0f840e2c] poll( <unfinished ...>
>>>>> [pid 75] [0f799444] kill(77, SIGXCPU) = 0
>>>>> [pid 75] [0f839834] brk(0x13525000) = 0x13525000
>>>>> [pid 75] [0f833558] write(1, "*** MEM CHUNK TAKEN:
>>>
>>>
>>> 8388608\n", 29***
>>>
>>>>> MEM CHUNK TAKEN: 8388608
>>>>> ) = 29
>>>>> [pid 75] [0f839834] brk(0x13535000) = 0x13535000
>>>>> [pid 75] [0f839834] brk(0x13545000) = 0x13545000
>>>>> [pid 75] [0f839834] brk(0x13d45000) = 0x13d45000
>>>>> [pid 75] [0f833558] write(1, "*** MEM CHUNK TAKEN:
>>>
>>>
>>> 8388608\n", 29***
>>>
>>>>> MEM CHUNK TAKEN: 8388608
>>>>> ) = 29
>>>>> [pid 76] [0f840e2c] <... poll resumed> [{fd=3,
>>>
>>>
>>> events=POLLIN}], 1,
>>>
>>>>> 2000) = 0
>>>>> [pid 76] [0f840e2c] --- SIGTERM (Terminated) ---
>>>>> #
>>>>>
>>>>>
>>>>
>>>>
>>>
>>
>
>
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