re: long longlong in libffi (powerpc)

[Andreas Tobler]

To follow up. (Sorry can't quote, webmail)

The problem I have is also visible on powerpc-linux.

Given this testcase:

static void closure_test_fn4(ffi_cif* cif,void* resp,void** args,
                             void* userdata)
 {
    *(ffi_arg*)resp =
      (int)*(long *)args[0] +(*(int *)args[1]) +
      /* (int)(*(float *)args[2]) + *(int *)args[3]*/ + (int)(long)userdata;

    printf("%d %d %d %d: %d\n",
           (int)*(long *)args[0], (*(int *)args[1]),
           /*  (int)(*(float *)args[2]), *(int *)args[3],*/ (int)(long)userdata,
           *(int*)resp);
 }

typedef int (*closure_test_type4)(long, int);

I run it with this definition:

      cl_arg_types[0] = &ffi_type_ulong;
      cl_arg_types[1] = &ffi_type_uint;
      cl_arg_types[2] = NULL;

Here I get a failure since ulong is 'mapped' onto longlong (8bytes)

setting the arg[0] type to &ffi_type_uint32 makes the testcase pass.

So I'm a bit confused. My long is 4 byte, my longlong 8. And the ABI from
sysv & darwin handles the long and the longlong different. (long !=longlong)


Do I follow a phantom or my one explain to me what I forget?

Thank you in advance.

Andreas