Extracting function name from the gimple call statement

[David Malcolm]

On Sun, 2021-10-10 at 23:04 +0530, Shubham Narlawar via Gcc wrote:
> Hello,
> 
> Is there a direct way to print the name of the function call in gimple
> call
> statement?
> 
> For example -
> 
> void bar() {
> a = foo();        //gimple* stmt
> }
> 
> I want to print "foo" from the above gimple*.
> 
> I traced debug_gimple_stmt(gimple*) but it seems complex to just print
> "foo".

Bear in mind that not every gimple call is calling a specific function;
it could be a jump through a function pointer.

  tree fn_ptr = gimple_call_fn (call);

However, for simple cases like the above, fn_ptr will be an ADDR_EXPR
node, and the zeroth operand of the ADDR_EXPR node will get you the
fndecl (of "foo").
  tree fn_decl = TREE_OPERAND (fn_ptr, 0);

Given a decl, you can then use:
  tree identifier = DECL_NAME (fn_decl);
to get the identifier node for the decl ("foo").

Finally, you can use
  const char *str = IDENTIFIER_POINTER (identifier)
to get a 0-terminated string from the identifier that you can print.

Hope this is helpful
Dave