GIMPLE clobber statement
Jason Merrill
jason@redhat.com
Tue Jul 16 13:34:00 GMT 2019
The clobber means that 'a' no longer has a value, presumably because it has
gone out of scope.
On Tue, Jul 16, 2019, 2:07 PM navya deepika Garakapati <
navyadeepika.garakapati@gmail.com> wrote:
> Hi everyone,
>
> We are investigating the optimization issue with GCC trunk code and we have
> the below gimple code like
>
> a = 1;
> __asm__ __volatile__("");
> _9 = &a;
> a ={v} {CLOBBER};
> _4 = _9;
> _1 = *_4;
> std::basic_ostream<char>::operator<< (&cout, _1);
>
>
> in the above gimple statements ,we would like to know the semantics of "a
> ={v} {CLOBBER}" and how this is interpreted by optimization ?
>
>
>
> Thank you
> Navya.
>
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