On 01/03/2010 11:25 PM, Richard Guenther wrote:
>> > char charray[sizeof(long)] = {...};
>> > long l = *(long*)charray; // ok
>
> not correct;) (the lvalue has to be of character type, yours is of
> type 'long' - the type of the actual object does not matter)
What would be correct instead is
memcpy ((char *) &l, charray, sizeof(long));
Paolo