Overload resolution compilation error

Ling-hua Tseng uranus@it.muds.net
Thu Jul 19 23:42:00 GMT 2007


On Thu, 19 Jul 2007 19:25:38 -0300, Rodolfo Lima wrote
> If I understand this correctly, when we have the following declarations:
> 
> template <class T> void foo() {}
> void foo() {}
> 
> The overload set for "&foo" at first contains all "void foo<T>()"  
> and "void foo()". Then, because of the presence of the latter, the 
> former should be eliminated. In the end, only "void foo()" remains,
>  and we have no ambiguity.
You forgot the hypothesis in the paragraph 1:
"The function
selected is the one whose type matches the target type required in the 
context. The target can be
— an object or reference being initialized (8.5, 8.5.3),
— the left side of an assignment (5.17),
— a parameter of a function (5.2.2),
— a parameter of a user-defined operator (13.5),
— the return value of a function, operator function, or conversion (6.6.3),
— an explicit type conversion (5.2.3, 5.2.9, 5.4), or
— a non-type template-parameter (14.3.2)."

What is the `target' in your program?
The answer is NOTHING.
So the set of overloaded functions is empty at beginning.

The following case can compile by g++:
  void (*fptr)() = &print;
It's because it has the `target'.
Your deduction can apply to this case, but it cannot apply to your example 
code.



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