gcc representation of long double on ia32

[Cristiano Pereira]

This 512 byte structure is saved by using the ia32
fxsave instruction.

Thanks,
Cristiano.

> I want to use the 512 byte structure which saves the
> floating point register state and convert it into a
> simulator that uses "long double" to represent each
> st(i) register. Each "st" register is represented as
> a
> 16 bytes with 6 most significant reserved. So only
> the
> first 10 bytes are the actual register value.
> 
> I want to take this 10 byte representation and
> convert
> it into a long double variable in my code. My
> question
> is how do I do it? Can I simply type cast it? 
> 
> Is there a correspondence between the 80bit register
> value and the represenation that gcc uses for a long
> double on ia32?
> 
> Would the below work?
> 
> unsigned char st[10]; // assume this contains the
> content of one of the st registers
> 
> long double n = *((long double *) st)
> 
> Would this work? If not, can someone please tell me
> how to do this exactly?
> 
> Thanks,
> Cristiano.
> 
> 
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