complex arithmetic and signed zero?

[Richard Henderson]

On Wed, Oct 12, 2005 at 01:48:49PM -0700, Steve Kargl wrote:
> Unfortunately, the point of my original question 
> was missed.  gcc is not following Annex G in n1124.pdf.
> In particular, see G.5.1  Multiplicative operators.
> 
> y = copysign(0, -1);
> z = I * y; /* This should be computed as (i1)*(-0) = -i0 */
>            /* Upon assignment to z, we have z = 0 - i0   */

File a bug then.


r~