How to get MIN_EXPR without using deprecated min operator

[chris jefferson]

Michael Cieslinski wrote:

>Consider the following short program:
>
>    #include <algorithm>
>    
>    void Tst1(short* __restrict__ SrcP, short* __restrict__ MinP, int Len)
>    {
>        for (int x=0; x<Len; x++)
>            MinP[x] = SrcP[x] <? MinP[x];
>    }
>    
>    void Tst2(short* __restrict__ SrcP, short* __restrict__ MinP, int Len)
>    {
>        for (int x=0; x<Len; x++)
>            MinP[x] = std::min(SrcP[x], MinP[x]);
>    }
>
>
>If I compile it with
>    gcc41 -O2 -ftree-vectorize -ftree-vectorizer-verbose=5
>function Tst1 gets vectorized but Tst2 not.
>
>The reason for this is <? results in a MIN_EXPR while std::min generates a
>conditional code.
>My question is, how can I get a MIN_EXPR without using the deprecated min <?
>operator?
>
>  
>
Out of interest, do you get vectorisation from:

MinP[x] = (SrcP[x]<MinP[x]) ? SrcP[x] : MinP[x];

Chris