g++4.0 diagnostic on casting a static const member initializer to a double
Matt Austern
austern@apple.com
Mon Jan 31 18:48:00 GMT 2005
On Jan 31, 2005, at 10:16 AM, Mark Mitchell wrote:
> Fariborz Jahanian wrote:
>> g++ 4.0 in FSF issues a diagnostic on the following test case:
>> template <class T> struct S {
>> static const double scd = (double)24;
>> };
>> test1.C:2: error: a cast to a type other than an integral or
>> enumeration type cannot appear in a constant-expression
>> Rewriting the above to:
>> template <class T> struct S {
>> static const double scd;
>> };
>> template <class T>
>> const double S<T>::scd = (double)24;
>> Compiles. Event though the diagnostic is clear in what it is saying,
>> but it seems to be a g++ bug
>> one way or the other.
>
> No, the input program is invalid. From [class.static.data]:
>
> "If a static data member is of const integral or const
> enumeration type, its declaration in the class definition can specify
> a constant-initializer which shall be an integral constant
> expression(_expr.const_)."
>
> The diagnostic could be better, but it is indeed accurate; if there's
> an initializer it must be integral constant-expression, and a cast to
> "double" cannot appear in such an expression.
Hm, I think it's stretching it a bit to call that diagnostic accurate.
The real user error is trying to initialize a static const double in
the first place, not the details of what we're trying to initialize it
with.
You're right that this code is invalid, but I think your average user
who gets this error message might be mystified about what's wrong.
--Matt
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