Bootstrap comparison failure

[Daniel Jacobowitz]

On Mon, Dec 19, 2005 at 01:18:21PM +0000, Richard Earnshaw wrote:
> I think the problem is PWDCMD (defaults to pwd) in the top-level
> makefile.  If your shell builds in pwd, then things will work.  If it
> doesn't then you'll get /bin/pwd which gives the canonical path.  Bash
> has a built-in pwd, and since on Linux /bin/sh is bash in disguise, it
> still uses the builtin.  A traditional Berkeley sh doesn't do this.
> 
> 'info pwd' on Linux says:
> 
>         `pwd' prints the fully resolved name of the current directory. 
>         That is, all components of the printed name will be actual
>         directory names--none will be symbolic links.
> 
> I suspect that if you run a bootstrap of gcc on Linux with
> PWDCMD=/bin/pwd it will fail too.

Yes, I saw a suggestion about this on IRC, but I tried it - it doesn't
fail.  The path that matters is not one ever returned by PWDCMD but the
one seen in $PWD by GCC; the only cd that's happened at that point is
done in the shell, by the toplevel Makefile, into 'gcc'.

-- 
Daniel Jacobowitz
CodeSourcery, LLC