Documentation bug for __builtin_choose_expr
Joseph S. Myers
joseph@codesourcery.com
Mon Nov 22 10:41:00 GMT 2004
On Mon, 22 Nov 2004, Jamie Lokier wrote:
> The documentation for __builtin_choose_expr says:
>
> -- Built-in Function: TYPE __builtin_choose_expr (CONST_EXP, EXP1, EXP2)
> You can use the built-in function `__builtin_choose_expr' to
> evaluate code depending on the value of a constant expression.
> This built-in function returns EXP1 if CONST_EXP, which is a
> constant expression that must be able to be determined at compile
> time, is nonzero. Otherwise it returns 0.
>
> This built-in function is analogous to the `? :' operator in C,
> except that the expression returned has its type unaltered by
> promotion rules. Also, the built-in function does not evaluate
> ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
> the expression that was not chosen. For example, if CONST_EXP
> ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
> evaluates to true, EXP2 is not evaluated even if it has
> ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
> side-effects.
> ^^^^^^^^^^^^^
>
> The way this is written implies that the underscored behaviour is
> different from the `? :' operator in C.
I'd think the idea is actually to say that it is different from normal
functions (built-in and otherwise), which inevitably evaluate all their
arguments before calling the function. (Although the syntax is that of a
built-in function, the implementation is that of a new keyword
__builtin_choose_expr handled specially in the parser.) Perhaps it should
say "Unlike most built-in functions, but like the ? : operator, ...".
--
Joseph S. Myers http://www.srcf.ucam.org/~jsm28/gcc/
jsm@polyomino.org.uk (personal mail)
joseph@codesourcery.com (CodeSourcery mail)
jsm28@gcc.gnu.org (Bugzilla assignments and CCs)
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