signed/unsigned right shift

[Andreas Schwab]

Christian Groessler <cpg@aladdin.de> writes:

> I have the following program which takes 2 unsigned short values,
> multiplies them and shifts the result right.
>
> This right shift gives a value with 1s bits at the high end.

This is correct.  The promotion rules let unsigned short promote to int,
since the latter can represent all values of the former.

Andreas.

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Andreas Schwab, SuSE Labs, schwab@suse.de
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