Help with bit-field semantics in C and C++
Mike Stump
mrs@apple.com
Tue Aug 24 20:22:00 GMT 2004
On Tuesday, August 24, 2004, at 12:32 PM, Gabriel Dos Reis wrote:
> Mike Stump <mrs@apple.com> writes:
>
> | On Tuesday, August 24, 2004, at 10:51 AM, Joe Buck wrote:
> | > On Tue, Aug 24, 2004 at 11:05:41AM -0600, Roger Sayle wrote:
> | >> The problem here is that a C++ enum can hold values outside the
> range
> | >> of it's type.
> |
> | > If it does, the program is not a valid ISO C++ program.
> |
> | ? What? Of course it is.
> |
> | I think the standard is perfectly clear in this area:
>
> You're quoting C99 which has a quite different semantics in this area.
> Joe is talking about C++.
While C++ is a times slightly different from C... It isn't all that
different:
7 A value of integral type can be explicitly converted to an enumeration
type. The value is unchanged if the integral value is within the
range of the enumeration values (_dcl.enum_). Otherwise, the result-
ing enumeration value is unspecified.
4 Each enumeration defines a type that is different from all other
types. Following the closing brace of an enum-specifier, each enumer-
ator has the type of its enumeration. Prior to the closing brace, the
type of each enumerator is the type of its initializing value. If an
initializer is specified for an enumerator, the initializing value has
the same type as the expression. If no initializer is specified for
the first enumerator, the type is an unspecified integral type. Oth-
erwise the type is the same as the type of the initializing value of
the preceding enumerator unless the incremented value is not repre-
sentable in that type, in which case the type is an unspecified inte-
gral type sufficient to contain the incremented value.
5 The underlying type of an enumeration is an integral type that can
represent all the enumerator values defined in the enumeration. It is
implementation-defined which integral type is used as the underlying
type for an enumeration except that the underlying type shall not be
larger than int unless the value of an enumerator cannot fit in an int
or unsigned int. If the enumerator-list is empty, the underlying type
is as if the enumeration had a single enumerator with value 0. The
value of sizeof() applied to an enumeration type, an object of enumer-
ation type, or an enumerator, is the value of sizeof() applied to the
underlying type.
This does not make the code _not_ C++. My contention remains, calling
the code not C++ is wrong and misleading.
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