Question on build_int_cst

[Nathan Sidwell]

Richard Kenner wrote:
> If the idea is to avoid having to do a conversion of an integer_type_node
> to another type (and hence waste node), why doesn't it call force_fit_type
> to ensure that the constant doesn't overflow the requested type?
it is supposed to be a drop in replacement for
	t = build_int_2 (x, y);
	TREE_TYPE (t) = z;
AFAICT most cases of use correctly condition x & y, so the overhead of
force_fit_type would be bad. Use,
	t = force_fit_type (build_int_cst (z, x, y), 0, 0, 0);
if you need to condition the range.

The idea of build_int_cst is to allow sharing of the int_csts so generated.

nathan

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