Modulus by constant

[Segher Boessenkool]

> Unfortunately, in this case b doesn't divide a because we're doing 
> modulus.
>
> I understand the general principle: I was wondering if anybody knew the
> code well because I suspect this is a "corner" case, being unsigned
> and having the constant being multiplied by look negative if it were 
> signed.

It is not unsigned.  The constant 255 is of type "int" and so the 
"unsigned
short" will be converted to "int", too.  (6.4.4.1/5 and 6.3.1.1/2 and 
6.3.1.8/1
and 6.5.5/3, in some order).


Segher