How to add a new operand to an expression?

[Carlo Wood]

On Thu, Oct 09, 2003 at 11:16:49AM -0400, Diego Novillo wrote:
> On Thu, 2003-10-09 at 11:05, Carlo Wood wrote:
> 
> > Can you be more specific?  I see nothing in make_node that
> > seems to need adjustment, gives me a clue or is even related
> > to CALL_EXPR :/.

> You may have missed the call to tree_size inside make_node.  From the
> debug dump you sent, it seems that you're losing track of how much
> memory was allocated to CALL_EXPR.  You'll have to debug from there.

tree_size() is automatically returning the correct size
after updating tree.def, of course.

tree_size() returns:

      return (sizeof (struct tree_exp)
	      + TREE_CODE_LENGTH (code) * sizeof (char *) - sizeof (char *));

The TREE_CODE_LENGTH is changed as a result of
changing the tree.def.


I am still clueless of why it doesn't work
the way I am doing this.

-- 
Carlo Wood <carlo@alinoe.com>