(printf) ("hello world\n");

[Andreas Schwab]

Eyal Lebedinsky <eyal@eyal.emu.id.au> writes:

> But without <stdio.h> the varargs attribute is not present

A varargs function is always a varargs function, whether it is prototyped
or not.  But without a proper prototype the behaviour is undefined.

Andreas.

-- 
Andreas Schwab, SuSE Labs, schwab@suse.de
SuSE Linux AG, Maxfeldstraße 5, 90409 Nürnberg, Germany
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