Thanks for "warning: statement with no effect"

[Ben Bucksch]

I just wrote a bunch of
    if (option == "4_5") hp_code_rate == FEC_4_5;
lines. gcc 3.2 told me
    "warning: statement with no effect"
I didn't see at first why, looked over the code a few times, until I 
noticed that I wrote "==" instead of "=". I would have neede ages to 
track this down. Thanks for this warning, it probably saved me a lot of 
hairs.

:-)
Ben

(P.S. I'm not subscribed to the list, just wanted to say thanks.)