long double format on I!64

Gabriel Dos Reis gdr@integrable-solutions.net
Thu Aug 29 01:37:00 GMT 2002


Bo Thorsen <bo@sonofthor.dk> writes:

| > I don't know how exactly I should interpret that since 80 bits don't
| > make 16 bytes.  I guess that means some bits are ignored.  If so I need
| > to know exactly which ones.
| 
| It's like x86, just with 6 bytes padding instead of 2. So the first 10 bytes 
| are the double.

OK, thanks a lot.

Hmm, I guess I'm going to have another funny day with this stuf.

-- Gaby



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