long double format on I!64
Gabriel Dos Reis
gdr@integrable-solutions.net
Thu Aug 29 01:37:00 GMT 2002
Bo Thorsen <bo@sonofthor.dk> writes:
| > I don't know how exactly I should interpret that since 80 bits don't
| > make 16 bytes. I guess that means some bits are ignored. If so I need
| > to know exactly which ones.
|
| It's like x86, just with 6 bytes padding instead of 2. So the first 10 bytes
| are the double.
OK, thanks a lot.
Hmm, I guess I'm going to have another funny day with this stuf.
-- Gaby
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