What does this mean?

[Mike Stump]

> To: Mike Stump <mrs@windriver.com>
> Cc: gcc@gcc.gnu.org
> From: nbecker@fred.net
> Date: 06 Apr 2001 16:41:49 -0400

>     >> In the following diagnostic, why does "(+rng)" mean?

> I don't understand why it says "(+rng)".  Why the plus sign?

That's a bug:

    case CONVERT_EXPR:
      if (VOID_TYPE_P (TREE_TYPE (t)))
      {
        print_left_paren (scratch_buffer);
	  dump_type (TREE_TYPE (t), flags);
	    print_right_paren (scratch_buffer);
	      dump_expr (TREE_OPERAND (t, 0), flags);
	      }
      else
      dump_unary_op ("+", t, flags);
      break;

CONVERT_EXPR is not necessarily part of the parse tree, sometimes it
is however.  I think it is safe to always remove them.  Also, the
parens aren't part of the parse tree.  The problem is we dump
partially digested things into error messages.

> Why the paranthesis?  I don't think my question is stupid.

Oh, sorry about that, I sometimes read things more literally than
people intend.  I answered the question of what does it mean, not why
do the extra characters (+) come out.  rng means +rng means (+rng).
The why is more embarrassing, and this embarrassment in conjunction
with my too literal reading is probably why I skipped the why part of
your question.

When dumping unary and binary operators, g++ has a habit of adding ()
to indicate bindings, even when the semantics are clear, and not
present in the source.