Volatile constants?

[Erik Mouw]

On Wed, 29 Mar 2000 18:49:04 +0100 (BST), Alasdair Baird wrote:
>  > > #define abs2(x) (x<0 ? -x : x)
>  > 
>  > <nitpick>
>  > You should define this as:
>  > 
>  >   #define abs2(x) ((x) < 0 ? (-x) : (x))
>  > 
>  > Rationale: see what happens with your version if you use abs2(2 - 3). The
>  > extra parentesis enforce the correct operator precedence.
> 
> I think that you might find the following to actually be correct though:
> 
>    #define abs2(x) ((x) < 0 ? -(x) : (x))

Yes, you're absolutely right.


Erik

-- 
In theory, practice and theory are the same, but in practice they 
are different -- Larry McVoy