c/7776: const char* p = "foo"; if (p == "foo") ... is compiled without warning!

[udbz@rz.uni-karlsruhe.de]

>Number:         7776
>Category:       c
>Synopsis:       const char* p = "foo"; if (p == "foo") ... is compiled without warning!
>Confidential:   no
>Severity:       serious
>Priority:       medium
>Responsible:    unassigned
>State:          open
>Class:          change-request
>Submitter-Id:   net
>Arrival-Date:   Fri Aug 30 09:06:00 PDT 2002
>Closed-Date:
>Last-Modified:
>Originator:     udbz@rz.uni-karlsruhe.de
>Release:        gcc-3.0.3
>Organization:
>Environment:

>Description:
The code construct below IMHO never makes sense and
should spill a warning.

It once caused me two months of work to discover this little
bug in the wine sources.
>How-To-Repeat:
#include <stdlib.h>
#include <stdio.h>

int main(int argc, const char** argv)
{
	const char * p = "Hello";

	if (p == "Hello") {
		fprintf(stderr, "1\n");
	} else {
		fprintf(stderr, "2\n");
	}
	return 0;
}
>Fix:

>Release-Note:
>Audit-Trail:
>Unformatted: