Fast Complex Division.

[craig@jcb-sc.com]

>Besides, reading Numerical Recipes on complex arithmetic, they scared me
>with another thing I hadn't given a thought:  One needs to choose a
>branch for taking "the" square root of a complex number (goes to show
>that I never use complex arithmetic - duh!):
>
>	There are two solutions to:		z1^2 = z2

Dunno if this is what you're referring to (I really don't "do math"
much, not since high school anyway)...from Fortran 90 standard on SQRT:

"A result of type complex is the principle value with the real part
greater than or equal to zero."

        tq vm, (burley)