GCC 9.2, partial specialization with non-type template parameters: bug or not?
Bence Kodaj
bence.kodaj@gmail.com
Sat Apr 18 19:51:31 GMT 2020
Dear list members,
I'd like to ask for your help with the following: in GCC 9.2., is partial
template specialization expected to work for *all* allowed non-type
template parameters of class type?
For a concrete example, please see the code below: it prints "false, true",
i.e., apparently, specializing T for X< Int > does not succeed, whereas it
does for Y< int >. Since Int is now (in C++20) allowed to be used as the
type of non-type template parameters, one would naively expect the
specialization of T for X< Int > to succeed just like the one for Y< int >
does. Is this belief justified, or am I missing something?
Disclaimer: I do realize that C++20 support in GCC 9 is experimental - I'm
just looking for clarity regarding this issue, i.e., does the C++20 (draft)
standard require that the code below print "true, true"?
Best regards,
Bence Kodaj
-------------
- Compiler version (from g++ -v): gcc version 9.2.1 20191102 (Ubuntu
9.2.1-17ubuntu1~18.04.1)
- Compilation command: g++ -std=c++2a main.cpp
- Code:
#include <iostream>
#include <type_traits>
struct Int {
constexpr Int(int v): value{ v } {}
const int value;
};
template< Int i >
struct X {};
template< int i >
struct Y {};
template< typename >
struct T : std::false_type {};
template< Int i >
struct T< X< i > > : std::true_type {};
template< int i >
struct T< Y< i > > : std::true_type {};
int main()
{
std::cout << std::boolalpha << T< X< 123 > >::value << ", " << T< Y<
123 > >::value << "\n";
return 0;
}
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