How 'experimental' is -std=c++0x

[Syncopated]

-std=c++0x support in gcc is said to be 'experimental'. Even a macro used to
detect c++0x is __GXX_EXPERIMENTAL_CXX0X__.

How experimental is 'experimental'? Does it mean that gcc has not much test
coverage with -std=c++0x compared to without? Does it mean there's a much
high chance of getting incorrect generated code even with source code that's
c++98?


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