Passing an address to a #define in C

[Andi Hellmund]

Hi Gus,
> This is because your code finally ends up with this expression:
> (void*)ptr>>  4
>
> and gcc doesn't allow the shift operation to be performed on pointer
> types. A possible solution to your problem could be the following code:
>
For the sake of completeness, if you're wondering why gcc requires an 
integer type, please check the C standard:

6.5.7 Bitwise shift operators
[...]

Constraints
   Each of the operands shall have integer type.

Best regards,
Andre-Marcel