why this testcase compile failed for gcc.

[zhang qingshan]

IMO, function pointer is a pointer which its type descriptor is a
function type ...

Any difference with the normal pointer?

On Fri, Feb 18, 2011 at 11:00 PM, Ian Lance Taylor <iant@google.com> wrote:
> zhang qingshan <steven.zhang54373@gmail.com> writes:
>
>> /* ------- test case -------------------*/
>> void x();
>> template <typename T>
>> void foo(const T*);
>>
>> int main() {
>>    foo(x);
>> }
>>
>> GCC 4.5 complains:
>>
>> a.cpp: In function 'int main()':
>> a.cpp:6: error: no matching function for call to 'foo(void (&)())'
>>
>> It seems that, const T * is resolved as void (&)());
>>
>> IMO, T --> void (), const T --> void (), const T * --> void (*)(), and
>> it should be leagle.
>
> You are confusing function pointers with pointers to data objects.  They
> are not the same thing in C++.  That is, a function pointer is not a
> special type of pointer.
>
> Ian
>