tan(pi/2) overflow

[richardcavell@mail.com]

> "Mathematically, the tangent function has singularities at odd 
multiples
> of pi/2. If the argument x is too close to one of these singularities,
> tan will signal overflow."

Since pi is irrational, pi/2 is also irrational and therefore 
infinitely long when represented in any base.  It is impossible to 
represent pi/2 in any floating point number format.  Therefore, it's 
impossible to pass pi/2 into tan() and impossible to hit a singularity. 
  You might like to feed it values that are very close to see whether 
you can make the result overflow.