Problem with derived templates

[andre maute]

Hi Axel,



first read
http://gcc.gnu.org/gcc-3.4/changes.html (C++ section)
http://gcc.gnu.org/develop.html#timeline



which indicates that gcc implements this rule since Apr 18 2004



then see my suggestion below



> I have a problem with a derived template class. It seams that all the
> members of the base class are not visible in the derived class. If I then
> make an instance of the derived class, I can access all members of the
> derived and the base class ??
>
> I'm using the CodeSourcery gcc4.4.1 (tried also 4.3.3, 4.3.2) to compile
> the following.
>
> Im sorry, my english is not very good, so please have a look at the
> sourecode:
>
>
> template <int N> class TBase {
> public:
>   int     Array[N];
>   int     fb1() { return Array[0]; };
> };        // everything is OK in TBase
>
> template <int NN> class TDerived : public TBase<NN> {
>   int     UU;
> public:
>   int     fc2() { return Array[0]; };  // error: 'Array' was not declared
> in this scope int     fc3() { return UU; };        // OK
>   int     fc4() { return fb1(); };     // error: .... 'fb1' must be
> available };



prefix the ones from TBase with this



	this->Array[0];
	this->fb1();



Regards
Andre