constants question

[Lars Poeschel]

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Am 06.02.2008 um 16:57 schrieb Eljay Love-Jensen:

> Hi Lars,
>
> Here bar is a variable:
> char const* const bar = "bar";
>
> I realize that bar is a const pointer to const char (array).  But  
> the bar identifier itself is a fixed variable, and not a constant.
>
> Here foo is a constant:
> char const foo[] = "foo";
>
> It's easy to conflate foo for a pointer, since, in C (and C++),  
> array constants degenerate into pointers quite promiscuously.  Just  
> look at them funny, and they turn into pointers, as if you had  
> typed &foo[0].
>
> Hence you can do this:
> char const* const quux[] =
> {
>  foo
> };
>
> But you cannot do this:
> char const* const baz[] =
> {
>  bar
> };
>
> C++ has slightly different rules, so it can do the later.
>
> HTH,
> --Eljay

Thanks a lot for this explanation, it is a bit more clear for me now!

Lars
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