trying to understand: "warning: function declaration isn't a prototype"

[Jay Vaughan]

>The warning means that the code does something like this:
>     extern int foo ();
>The warning message will include a file name and line number you can
>use to see where this is happening.
>

yes, i understand this - i do not want to ignore this warning, i want 
to understand why the warning is emitted in the first place ..


-- 

;

Jay Vaughan